Foundation Engineering

Vibration Amplitude Analysis for Machinery Foundations

Evaluate foundation vibration response using single-degree-of-freedom models, ISO 10816 velocity limits, and API 684 criteria per ACI 351.3R.

Frequency Ratio Target

r < 0.5 or r > 1.5

Avoid resonance zone (0.7-1.3)

ISO 10816 Zone A

< 1.8 mm/s RMS

Newly commissioned machines

Mass Ratio

3:1 to 5:1

Foundation to machine weight

1. Overview

Compressor foundations experience periodic dynamic forces from unbalanced masses, gas pressure pulsations, and inertia effects. The foundation must be designed so that vibration amplitudes remain below acceptable limits for equipment integrity, personnel comfort, and adjacent structure protection.

Displacement

mils (peak-to-peak)

Primary criterion for low-speed machines

Velocity

in/s or mm/s RMS

ISO 10816 primary criterion

Acceleration

g's

Important for high-frequency excitation

Resonance

Amplification

Avoid r = 0.7-1.3 range

Vibration Sources in Compressor Systems

SourceFrequencyMagnitudeMitigation
Primary unbalance1x RPMHighCounterweights, balancing
Secondary unbalance2x RPMModerateOpposed cylinders, foundation mass
Gas pressure pulsation1x-6x RPMVariablePulsation bottles, orifice plates
Crosshead forces1x, 2x RPMModerateFoundation design, anchoring
Torque fluctuation0.5x-6x RPMLow-moderateFlywheel, coupling selection
Piping vibrationVariousVariableSupports, clamps, snubbers
Design philosophy: The goal is either (1) a massive foundation with natural frequency well below excitation frequency (under-tuned), or (2) a stiff foundation with natural frequency well above excitation (over-tuned). Never allow the natural frequency to fall within 20-30% of any excitation frequency.

2. Dynamic Response Theory

The foundation-soil system is modeled as a single-degree-of-freedom (SDOF) or multi-degree-of-freedom (MDOF) system. The SDOF model captures the essential dynamics for preliminary design.

SDOF Forced Vibration

Equation of Motion: m * x'' + c * x' + k * x = F_0 * sin(omega * t) Where: m = Total mass (foundation + machine) (lb-s^2/in or slugs) c = Damping coefficient (lb-s/in) k = Spring stiffness (lb/in) F_0 = Unbalanced force amplitude (lb) omega = Excitation circular frequency (rad/s) Natural Frequency: omega_n = sqrt(k / m) (rad/s) f_n = omega_n / (2 * pi) (Hz) RPM_n = f_n * 60 (RPM) Frequency Ratio: r = omega / omega_n = f_excitation / f_natural Damping Ratio: D = c / (2 * sqrt(k * m)) Typical for soil: D = 0.02 - 0.10

Steady-State Amplitude

For constant force excitation (F_0 * sin(omega*t)): X = (F_0 / k) / sqrt[(1 - r^2)^2 + (2*D*r)^2] Dynamic Magnification Factor (DMF): DMF = 1 / sqrt[(1 - r^2)^2 + (2*D*r)^2] At resonance (r = 1): DMF = 1 / (2*D) For D = 0.05: DMF = 10 (dangerous amplification) For rotating unbalance (F = m_e * e * omega^2): X = (m_e * e / M) * r^2 / sqrt[(1 - r^2)^2 + (2*D*r)^2] Where: m_e = Eccentric mass (slugs) e = Eccentricity (in) M = Total system mass (slugs)

Phase Angle

Phase lag between force and response: phi = arctan[2*D*r / (1 - r^2)] At r = 1 (resonance): phi = 90 deg At r << 1: phi approaches 0 deg (in phase) At r >> 1: phi approaches 180 deg (out of phase)

Vibration Parameters Relationship

ParameterSymbolRelationshipUnits
Displacement (peak)XXmils or mm
Velocity (peak)VV = omega * Xin/s or mm/s
Acceleration (peak)aa = omega^2 * Xin/s^2 or g
RMS from peak-RMS = Peak / sqrt(2)Same units
Peak-to-peakX_ppX_pp = 2 * X_peakmils or mm

3. Vibration Limits & Standards

Multiple industry standards define acceptable vibration levels. The applicable standard depends on machine type, speed, and mounting configuration.

ISO 10816 Vibration Severity Classification

ISO 10816 defines vibration severity zones based on RMS velocity measured on the bearing housing or foundation.

ZoneVelocity (mm/s RMS)Velocity (in/s RMS)Condition
Zone A< 1.8< 0.071Newly commissioned; excellent
Zone B1.8 - 4.50.071 - 0.177Acceptable for long-term operation
Zone C4.5 - 11.20.177 - 0.441Restricted operation; corrective action
Zone D> 11.2> 0.441Severe; damage imminent

Note: Values shown are for Group 2 machines (medium machines, 15-300 kW, rigid foundation). ISO 10816-3 provides specific criteria by machine class.

API 684 Criteria for Rotating Equipment

CriterionLimitApplication
Foundation amplitude< 1.0 mil p-p at operating speedBlock foundations
Foundation velocity< 0.12 in/s peakAll machinery foundations
Bearing housing vibration< sqrt(12,000/RPM) mils p-pAPI 617, 618 machines
Amplification at resonance< 5x static deflectionDesign limit for damping

ACI 351.3R Amplitude Limits

Allowable vibration displacement (ACI 351.3R): For reciprocating machines: X_allow = 150 / f (mils peak, where f = frequency in CPM) Example: At 600 RPM: X_allow = 150/600 = 0.25 mils peak For rotating machines: X_allow = 80 / f (mils peak) Velocity-based criterion: V_allow < 0.10 in/s peak (general) V_allow < 0.06 in/s peak (sensitive equipment nearby) V_allow < 0.20 in/s peak (robust industrial)

Frequency Ratio Design Criteria

Frequency Ratio (r)Design RegionDMF (D=0.05)Assessment
< 0.5Under-tuned (safe)< 1.33Massive foundation approach
0.5 - 0.7Caution zone1.33 - 2.13Verify amplitude acceptable
0.7 - 1.3Resonance zone2.13 - 10.0+UNACCEPTABLE - redesign
1.3 - 1.5Caution zone2.13 - 1.33Verify amplitude acceptable
> 1.5Over-tuned (safe)< 1.33Stiff foundation approach
Critical requirement: The foundation natural frequency must not coincide with 1x RPM, 2x RPM, or any significant harmonic of the operating speed. ACI 351.3R requires checking all harmonics up to the 6th order for reciprocating compressors.

4. Transmissibility & Isolation

Transmissibility describes the fraction of dynamic force transmitted from the machine through the foundation to the soil (or conversely, from the soil to the machine).

Force Transmissibility: TR = F_transmitted / F_applied TR = sqrt[1 + (2*D*r)^2] / sqrt[(1 - r^2)^2 + (2*D*r)^2] For isolation (TR < 1.0): Required: r > sqrt(2) = 1.414 (regardless of damping) Isolation efficiency: IE = (1 - TR) * 100% At r = 3.0, D = 0.05: TR = 0.125 (87.5% isolation) At r = 5.0, D = 0.05: TR = 0.042 (95.8% isolation)

Isolation System Selection

Isolator TypeFrequency RangeIsolation %Application
Steel springs2-8 Hz85-98%Large reciprocating compressors
Rubber pads (neoprene)8-25 Hz70-90%Small to medium machines
Air springs1-5 Hz90-99%Precision, sensitive equipment
Inertia block (no springs)N/A30-60%Mass addition for amplitude reduction
Cork/fiberglass pads15-40 Hz50-80%High-frequency isolation
Important tradeoff: Adding damping reduces peak amplitude at resonance but decreases isolation effectiveness at high frequency ratios. For compressor foundations, moderate damping (D = 0.03-0.08) provides a practical balance between resonance protection and force isolation.

5. Soil-Structure Interaction

The soil provides both stiffness (spring) and energy dissipation (damping) for the foundation system. Soil dynamic properties directly affect natural frequencies and vibration amplitudes.

Equivalent Soil Springs (Rigid Circular Foundation)

Lysmer analog for vertical vibration: k_v = 4 * G * r_0 / (1 - nu) Horizontal (sliding): k_h = 32 * (1 - nu) * G * r_0 / (7 - 8*nu) Rocking: k_r = 8 * G * r_0^3 / [3 * (1 - nu)] Torsion: k_t = 16 * G * r_0^3 / 3 Where: G = Dynamic shear modulus (lb/in^2) r_0 = Equivalent radius of foundation (ft) r_0 = sqrt(A / pi) for vertical and sliding r_0 = (4*I / pi)^(1/4) for rocking nu = Poisson's ratio A = Foundation base area (ft^2) I = Moment of inertia of base area (ft^4)

Radiation Damping

Geometric (radiation) damping ratios: Vertical: D_v = 0.425 / sqrt(B_z) B_z = (1 - nu) * m / (4 * rho * r_0^3) Horizontal: D_h = 0.288 / sqrt(B_x) B_x = (7 - 8*nu) * m / (32 * (1-nu) * rho * r_0^3) Rocking: D_r = 0.15 / [(1 + B_theta) * sqrt(B_theta)] B_theta = 3*(1-nu)*I_theta / (8 * rho * r_0^5) Where: rho = Soil mass density (slugs/ft^3) I_theta = Mass moment of inertia about rocking axis B_z, B_x, B_theta = Dimensionless mass ratios Note: Radiation damping is typically 3-15% for vertical, 2-8% for horizontal, and 1-5% for rocking.

Coupled Rocking-Sliding Mode

Horizontal and rocking motions are coupled because horizontal forces applied above the foundation base create moments. A coupled analysis is required for accurate results.

ModeDOFTypical Natural FreqPrimary Concern
Vertical115-40 HzVertical displacement at base
Horizontal110-30 HzSliding at CG elevation
Rocking18-25 HzAngular rotation, top-of-block amplitude
Coupled rock-slide2Two frequenciesMost critical for tall foundations
Torsion120-60 HzUneven cylinder firing, moment couples

6. Worked Examples

Example 1: Vertical Vibration Amplitude

Given: Reciprocating compressor: 900 RPM, primary unbalanced force = 5,000 lb Foundation + machine mass: 80,000 lb (m = 80,000/386.4 = 207 slugs) Soil: Dense sand, G = 3,000 ksf, nu = 0.30 Foundation base: 10 ft x 14 ft Step 1: Equivalent radius A = 10 * 14 = 140 ft^2 r_0 = sqrt(140 / pi) = 6.68 ft Step 2: Vertical spring stiffness k_v = 4 * G * r_0 / (1 - nu) k_v = 4 * 3,000 * 1,000 * 6.68 / (1 - 0.30) * (1/144) k_v = 4 * 3,000,000 * 6.68 / 0.70 = 114.5 x 10^6 lb/ft k_v = 114.5 x 10^6 / 12 = 9.54 x 10^6 lb/in Step 3: Natural frequency omega_n = sqrt(k_v / m) = sqrt(9.54 x 10^6 / 207) omega_n = 214.7 rad/s f_n = 214.7 / (2 * pi) = 34.2 Hz = 2,050 RPM Step 4: Frequency ratio r = 900 / 2,050 = 0.439 (< 0.5, under-tuned -- GOOD) Step 5: Damping (assume D = 0.05 total) DMF = 1 / sqrt[(1 - 0.439^2)^2 + (2*0.05*0.439)^2] DMF = 1 / sqrt[(1 - 0.193)^2 + (0.0439)^2] DMF = 1 / sqrt[0.651 + 0.00193] = 1 / 0.808 = 1.24 Step 6: Vibration amplitude X_static = F_0 / k_v = 5,000 / 9.54 x 10^6 = 0.000524 in X_dynamic = X_static * DMF = 0.000524 * 1.24 = 0.00065 in = 0.65 mils peak Step 7: Velocity omega = 900 * 2*pi / 60 = 94.2 rad/s V = omega * X = 94.2 * 0.00065 = 0.061 in/s peak V_rms = 0.061 / sqrt(2) = 0.043 in/s = 1.1 mm/s (Zone A -- OK)

Example 2: Checking Multiple Harmonics

Given: Same compressor at 900 RPM, f_n = 34.2 Hz Check harmonics: 1x: 900 RPM = 15.0 Hz, r = 15.0/34.2 = 0.44 -- OK 2x: 1,800 RPM = 30.0 Hz, r = 30.0/34.2 = 0.88 -- RESONANCE ZONE 3x: 2,700 RPM = 45.0 Hz, r = 45.0/34.2 = 1.32 -- Caution 4x: 3,600 RPM = 60.0 Hz, r = 60.0/34.2 = 1.75 -- OK Problem: 2x harmonic (secondary unbalance) at r = 0.88 falls in resonance zone (0.7-1.3). Solutions: 1. Increase foundation mass to lower f_n below 21.4 Hz (so 2x at 30 Hz gives r > 1.4) 2. Stiffen soil (compaction) to raise f_n above 42.9 Hz (so 2x at 30 Hz gives r < 0.7) 3. Reduce 2x unbalanced force through opposed-pair balancing