Temperature Drop

Engineering fundamentals for pipeline heat transfer

1. Heat Transfer Fundamentals

Fluid temperature changes along a pipeline due to heat exchange with surroundings. For hot fluids, temperature drops; for cold fluids (below ambient), temperature rises toward equilibrium.

Heat Transfer Mechanisms

🔄 Heat Transfer Resistances
Cross-section of insulated pipe showing thermal resistance layers: (1) Internal film (h_i), (2) Pipe wall (k_steel), (3) Insulation layer (k_ins), (4) External coating, (5) Soil or air (h_o or k_soil). Show temperature profile dropping through each layer from T_fluid to T_ambient. Label each resistance R₁ through R₅. Include radii r₁, r₂, r₃ for each interface.

Key Parameters

Parameter Symbol Units
Overall heat transfer coefficient U BTU/hr·ft²·°F
Thermal conductivity k BTU/hr·ft·°F
Convection coefficient h BTU/hr·ft²·°F
Mass flow rate lb/hr
Specific heat Cp BTU/lb·°F

2. Overall Heat Transfer Coefficient

The overall U-value combines all thermal resistances in series from fluid to surroundings.

General Equation

Overall U (based on outside area): 1/U_o = (r_o/r_i)/h_i + r_o×ln(r_o/r_i)/k_pipe + r_o×ln(r_ins/r_o)/k_ins + 1/h_o Where: U_o = Overall coefficient (BTU/hr·ft²·°F) r_i = Inside radius (ft) r_o = Outside radius of pipe (ft) r_ins = Outside radius of insulation (ft) h_i = Internal convection coefficient h_o = External convection coefficient k = Thermal conductivity

Thermal Conductivity Values

Material k (BTU/hr·ft·°F)
Carbon steel 26–30
Stainless steel 8–10
Calcium silicate insulation 0.032–0.045
Mineral wool 0.023–0.030
Polyurethane foam 0.012–0.018
Dry soil 0.15–0.25
Wet soil 0.6–1.0
Saturated soil 1.0–1.5

Convection Coefficients

Internal (turbulent flow, Dittus-Boelter): h_i = 0.023 × (k/D) × Re^0.8 × Pr^0.3 External (natural convection, horizontal pipe): h_o ≈ 1.0–2.0 BTU/hr·ft²·°F (still air) h_o ≈ 3–10 BTU/hr·ft²·°F (light wind) Typical pipeline U-values: Bare pipe in still air: 1.5–2.5 BTU/hr·ft²·°F Insulated pipe: 0.1–0.5 BTU/hr·ft²·°F Buried pipe: 0.3–1.0 BTU/hr·ft²·°F

3. Temperature Profile Equations

Temperature varies exponentially along the pipeline, approaching ambient asymptotically.

Steady-State Temperature Profile

Temperature at distance L: T(L) = T_amb + (T_inlet - T_amb) × exp(-U×π×D×L / (ṁ×Cp)) Or using decay constant: T(L) = T_amb + (T_inlet - T_amb) × exp(-L/L_c) Where: L_c = ṁ×Cp / (U×π×D) = characteristic length (ft) At L = L_c, temperature difference drops to 37% of inlet difference.

Heat Loss Rate

Total heat loss: Q = ṁ × Cp × (T_inlet - T_outlet) Heat loss per unit length: q = U × π × D × (T_fluid - T_amb) [BTU/hr·ft] Log mean temperature difference: LMTD = (ΔT_inlet - ΔT_outlet) / ln(ΔT_inlet/ΔT_outlet) Q_total = U × A × LMTD
📈 Temperature Profile Along Pipeline
Graph with Distance (miles) on X-axis, Temperature (°F) on Y-axis. Show exponential decay curve from T_inlet approaching T_ambient asymptotically. Mark characteristic length L_c where ΔT drops to 37%. Show second curve for insulated pipeline (slower decay). Include horizontal dashed line for ambient temperature. Label key temperatures and distances.

4. Buried Pipeline Calculations

For buried pipelines, soil thermal resistance replaces external convection. Burial depth significantly affects heat transfer.

Soil Thermal Resistance

Soil resistance (per unit length): R_soil = ln(2H/D + √((2H/D)² - 1)) / (2π × k_soil) Simplified for H >> D: R_soil ≈ ln(4H/D) / (2π × k_soil) Where: H = Depth to pipe centerline (ft) D = Pipe outside diameter (ft) k_soil = Soil thermal conductivity (BTU/hr·ft·°F)

Buried Pipeline U-Value

Overall U for buried insulated pipe: 1/(U×D) = 1/(h_i×D_i) + ln(D_o/D_i)/(2k_pipe) + ln(D_ins/D_o)/(2k_ins) + R_soil U = 1 / (D × Σ Resistances)

Ground Temperature

Depth (ft) Temperature Variation
Surface Follows air temperature
3–4 ±15°F seasonal swing
6–8 ±5°F seasonal swing
> 15 Nearly constant (≈ annual mean air temp)
Soil moisture: Wet soil conducts heat 3–5× better than dry soil. Design should consider worst-case (wet) conditions for cooling applications and best-case (dry) for heating/maintaining temperature.

5. Applications

Why Temperature Matters

Example Calculation

Given: 12" buried gas pipeline, 50 miles, inlet 120°F, ground temp 55°F, flow 100 MMSCFD, U = 0.5 BTU/hr·ft²·°F

Step 1: Mass flow rate
ṁ = 100×10⁶ × 0.044 lb/scf / 24 hr = 183,000 lb/hr

Step 2: Characteristic length
Cp = 0.55 BTU/lb·°F, D = 1 ft
L_c = (183,000 × 0.55) / (0.5 × π × 1)
L_c = 64,000 ft = 12.1 miles

Step 3: Outlet temperature
L = 50 miles = 264,000 ft
T_out = 55 + (120-55) × exp(-264,000/320,000)
T_out = 55 + 65 × 0.44 = 55 + 29 = 84°F

Step 4: Heat loss
Q = 183,000 × 0.55 × (120-84) = 3.6 MM BTU/hr

Temperature Maintenance Options

Method Application
Insulation Reduce heat loss, slow cooling rate
Electric heat tracing Maintain minimum temp, prevent freezing
Steam tracing Process plants, short runs
Hot oil/water circulation Subsea flowlines, heavy oil
Direct electrical heating (DEH) Subsea pipelines

References